On Partial Differentiation
This apparently isn’t on my a-level syllabus (or at least integration of this type isn’t) but, thanks to my pure teacher - who is ancient, a genius and a legend, I now know how to do it…
So differentiating with two variables
Lets take a simple equation like
To differentiate this we need to differentiate in respect to x and y separately. When we do this we are effectively ignoring x or y and taking a tangent of a line as if x or y was a constant so you just have a plane.
So if we want the rate of change of z in terms of x then we treat y as a constant.
So as you can see we have differentiated the x term as normal but the y term has been treated like a constant and has thus disappeared. This is our first partial derivative. Our second partial derivative is,
So therefore at x=4, y=2.
The gradient in the y-direction is 4 and in the x-direction is 8.
Now from this we can work out the tangent plane at x=4, y=2.
The formula for this will be,
Where m and n are the gradients in their respective directions.
So when x=4, y=2.
And
So
So our tangent plane is

To verify this we can solve
simultaneously and as the original formula is of degree 2 the should only be one solution, at (4,2,20).










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solving y mx b said this on May 29, 2008 at 4:33 am